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Jefferson Township, Brown County, Ohio

Jefferson Township, Brown County, Ohio
Township
Farmstead southeast of Russellville
Farmstead southeast of Russellville
Location of Jefferson Township in Brown County
Location of Jefferson Township in Brown County
Coordinates: 38°51′21″N 83°47′28″W / 38.85583°N 83.79111°W / 38.85583; -83.79111Coordinates: 38°51′21″N 83°47′28″W / 38.85583°N 83.79111°W / 38.85583; -83.79111
Country United States
State Ohio
County Brown
Area
 • Total 23.47 sq mi (60.78 km2)
 • Land 23.45 sq mi (60.74 km2)
 • Water 0.01 sq mi (0.03 km2)
Elevation 925 ft (282 m)
Population (2010)
 • Total 1,433
 • Density 61/sq mi (23.6/km2)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
FIPS code 39-38528
GNIS feature ID 1085799

Jefferson Township is one of the sixteen townships of Brown County, Ohio, United States. The 2010 census found 1,433 people in the township, 872 of whom lived in the unincorporated portions of the township.

Located in the eastern part of the county, it borders the following townships:

The village of Russellville is located in northern Jefferson Township.

It is one of twenty-four .

Jefferson Township was established in 1853 from land given by Byrd Township.

The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer, who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.


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