United States presidential election in Arizona, 1992

United States presidential election in Arizona, 1992

1988 ← November 3, 1992 → 1996

Nominee George H.W. Bush Bill Clinton Ross Perot Party Republican Democratic Independent Home state Texas Arkansas Texas Running mate Dan Quayle Al Gore Electoral vote 8 0 0 Popular vote 572,086 543,050 353,741 Percentage 38.5% 36.5% 23.8%

County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

George H. W. Bush
Republican

Bill Clinton
Democratic

The 1992 United States presidential election in Arizona took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Arizona was won by incumbent President George H.W. Bush (R-Texas) with 38.47% of the popular vote over Governor Bill Clinton (D-Arkansas) with 36.52%. Businessman Ross Perot (I-Texas) finished in third with 23.79% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush. Bush very narrowly won in Arizona by a margin of 1.95%, and Clinton went on to win the state in the 1996 election narrowly over Bob Dole.