United States presidential election in Arkansas, 1988
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County Results
Dukakis—70-80%
Dukakis—60-70%
Dukakis—50-60%
Bush—50-60%
Bush—60-70%
Bush—70-80%
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The 1988 United States presidential election in Arkansas took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Arkansas voters chose 6 electors to the Electoral College, which selected the President and Vice President.
Arkansas was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.
Arkansas weighed in for this election as 3% more Republican than the national average.
The presidential election of 1988 was a very partisan election for Arkansas, with nearly 99% of the electorate voting for either the Democratic or Republican parties. The vast majority of the counties voted primarily Republican, including the highly populated center of Pulaski County. In typical form for the time, the southeastern portion of the state (which touches the Mississippi River) continued to turn out primarily Democratic during this election, including areas such as Desha County and Phillips County.
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