United States presidential election in Delaware, 1988

United States presidential election in Delaware, 1988

← 1984 November 8, 1988 1992 →
Nominee George H. W. Bush Michael Dukakis Party Republican Democratic Home state Texas Massachusetts Running mate Dan Quayle Lloyd Bentsen Electoral vote 3 0 Popular vote 139,639 108,647 Percentage 55.9% 43.5%
County Results   Dukakis—70-80%   Dukakis—60-70%   Dukakis—50-60%   Bush—50-60%   Bush—60-70%   Bush—70-80%
President before election Ronald Reagan Republican Elected President George H. W. Bush Republican

Ronald Reagan
Republican

George H. W. Bush
Republican

The 1988 United States presidential election in Delaware took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Delaware voters chose 3 electors to the Electoral College, which selected the President and Vice President.

Delaware was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.

Delaware weighed in for this election as about 1% more Republican than the national average. As of 2016, this is the last time that the Republican nominee carried Delaware.

The presidential election of 1988 was a very partisan election for Delaware, with nearly 99.5% of the electorate voting for either the Democratic or Republican parties, and only four political parties on the ballot, statewide. All counties in Delaware voted in majority for Bush.