United States presidential election in Iowa, 1948

United States presidential election in Iowa, 1948

← 1944 November 2, 1948 1952 →
All 10 Iowa votes to the Electoral College
Nominee Harry S. Truman Thomas Dewey Party Democratic Republican Home state Missouri New York Running mate Alben W. Barkley Earl Warren Electoral vote 10 0 Popular vote 522,380 494,018 Percentage 50.3% 47.6%
President before election Harry S. Truman Democratic Elected President Harry S. Truman Democratic

Harry S. Truman
Democratic

Harry S. Truman
Democratic

The 1948 United States presidential election in Iowa took place on November 2, 1948, as part of the 1948 United States presidential election. Iowa voters chose ten representatives, or electors, to the Electoral College, who voted for President and Vice President.

Iowa was won by incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 50.31% of the popular vote, against Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 47.58% of the popular vote.

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