United States presidential election in New Mexico, 1996

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November 5, 1996

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Nominee	Bill Clinton	Bob Dole	Ross Perot
Party	Democratic	Republican	Reform
Home state	Arkansas	Kansas	Texas
Running mate	Al Gore	Jack Kemp	Pat Choate
Electoral vote	5	0	0
Popular vote	273,495	232,751	32,257
Percentage	49.2%	41.9%	5.8%

County Results

Clinton—70-80%

Clinton—60-70%

Clinton—50-60%

Clinton—40-50%

Dole—40-50%

Dole—50-60%

Dole—60-70%

President before election

Bill Clinton
Democratic

Elected President

Bill Clinton
Democratic

The 1996 United States presidential election in New Mexico took place on November 5, 1996. All 50 states and the District of Columbia, were part of the 1996 United States presidential election. New Mexico voters chose 5 electors to the Electoral College, which selected the President and Vice President.

New Mexico was won by incumbent United States President Bill Clinton of Arkansas, who was running against Kansas Senator Bob Dole. Clinton ran a second time with former Tennessee Senator Al Gore as Vice President, and Dole ran with former New York Congressman Jack Kemp.

New Mexico weighed in for this election as 1% more Republican than the national average.

The presidential election of 1996 was a very multi-partisan election for New Mexico, with nearly 10% of the electorate voting for third-party candidates, and two third-party candidates receiving more than 1% of the vote. The majority of counties in New Mexico turned out for Clinton, including the highly populated areas of Doña Ana County, Santa Fe County and Albuquerque's Bernalillo County.

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