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United States presidential election in New York, 1836

United States presidential election in New York, 1836
New York (state)
← 1832 November 3 - December 7, 1836 1840 →
  MVanBuren.png William Henry Harrison by James Reid Lambdin, 1835-crop.jpg
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard Mentor Johnson Francis Granger
Electoral vote 42 0
Popular vote 166,795 138,548
Percentage 54.63 45.47

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic


Andrew Jackson
Democratic

Martin Van Buren
Democratic

The 1836 United States presidential election in New York took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose forty-two representatives, or electors to the Electoral College, who voted for President and Vice President.

New York voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New York by a margin of 9.26%.


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