United States presidential election in New York, 1884

United States presidential election in New York, 1884

1880 ← November 4, 1884 → 1888

Nominee Grover Cleveland James G. Blaine Party Democratic Republican Home state New York Maine Running mate Thomas A. Hendricks John A. Logan Electoral vote 36 0 Popular vote 563,154 562,005 Percentage 48.25% 48.15%

County Results Cleveland   40-50%   50-60%   60-70% Blaine   40-50%   50-60%   60-70%

President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

Cleveland

Blaine

Chester A. Arthur
Republican

Grover Cleveland
Democratic

The 1884 United States presidential election in New York took place on November 4, 1884. All contemporary 38 states were part of the 1884 United States presidential election. New York voters chose 36 electors to the Electoral College, which selected the President and Vice President.

New York was won by the Democratic nominees, Governor Grover Cleveland of New York and his running mate former Senator and Governor Thomas A. Hendricks of Indiana. Cleveland and Hendricks defeated the Republican nominees, former Secretary of State and Senator James G. Blaine of Maine and his running mate Senator John A. Logan of Illinois.

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