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United States presidential election in New York, 1896

United States presidential election in New York, 1896
New York (state)
← 1892 November 3, 1896 1900 →
  Mckinley.jpg William Jennings Bryan 2.jpg
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 36 0
Popular vote 819,838 551,369
Percentage 57.58% 38.72%

New york presidential results 1896.svg
County Results
  Bryan—50-60%
  McKinley—50-60%
  McKinley—60-70%
  McKinley—70-80%

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican


Grover Cleveland
Democratic

William McKinley
Republican

The 1896 United States presidential election in New York took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. New York voters chose 36 electors to the Electoral College, which selected the President and Vice President.

New York was won by the Republican nominees, former Governor William McKinley of Ohio and his running mate corporate lawyer Garret Hobart of New Jersey. McKinley and Hobart defeated the Democratic nominees, former Congressman William Jennings Bryan of Nebraska and his running mate industrialist Arthur Sewall of Maine. Bryan also ran and received votes on the Populist Party line, with running mate Congressman Thomas E. Watson of Georgia.


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