United States presidential election in New York, 1940

United States presidential election in New York, 1940

← 1936 November 5, 1940 1944 →
Nominee Franklin D. Roosevelt Wendell Willkie Party Democratic Republican Home state New York New York Running mate Henry A. Wallace Charles L. McNary Electoral vote 47 0 Popular vote 3,251,918 3,027,478 Percentage 51.50% 47.95%
County Results   Roosevelt—60-70%   Roosevelt—50-60%   Willkie—50-60%   Willkie—60-70%   Willkie—70-80%
President before election Franklin D. Roosevelt Democratic Elected President Franklin D. Roosevelt Democratic

Franklin D. Roosevelt
Democratic

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in New York took place on November 5, 1940. All contemporary 48 states were part of the 1940 United States presidential election. New York voters chose 47 electors to the Electoral College, which selected the president and vice president.

New York was won by incumbent Democratic President Franklin D. Roosevelt of New York, who was running against Republican businessman Wendell Willkie of Indiana. Roosevelt ran with incumbent Vice President Henry A. Wallace of Iowa, and Willkie ran with Senator Charles L. McNary of Oregon.

A former Governor of New York who had easily carried the state in his previous two presidential campaigns, Franklin Roosevelt again won New York State in 1940, but by a much closer margin. Roosevelt took 51.50% of the vote versus Wendell Willkie's 47.95%, a margin of 3.55%.