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United States presidential election in Ohio, 1836

United States presidential election in Ohio, 1836
Ohio
← 1832 November 3 – December 7, 1836 1840 →
  WHenryHarrison.png MartinVanBuren.png
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate Francis Granger Richard Johnson
Electoral vote 21 0
Popular vote 104,958 96,238
Percentage 51.87% 47.56%

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic


Andrew Jackson
Democratic

Martin Van Buren
Democratic

The 1836 United States presidential election in Ohio took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose twenty-one representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio voted for Whig candidate William Henry Harrison over Democratic candidate Martin Van Buren. Harrison won Ohio by a margin of 4.31%.


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