United States presidential election in Pennsylvania, 1912

United States presidential election in Pennsylvania, 1912

← 1908 November 5, 1912 1916 →
Nominee Theodore Roosevelt Woodrow Wilson Party Progressive Democratic Home state New York New Jersey Running mate Hiram Johnson Thomas R. Marshall Electoral vote 38 0 Popular vote 444,894 395,637 Percentage 36.53% 32.49%   Nominee William Howard Taft Eugene Victor Debs Party Republican Socialist Home state Ohio Indiana Running mate Nicholas M. Butler (replaced James S. Sherman) Emil Seidel Electoral vote 0 0 Popular vote 273,360 83,614 Percentage 22.45% 6.87%
County results* *Red denotes a Taft victory—Debs did not carry any counties
President before election William Howard Taft Republican Elected President Woodrow Wilson Democratic

(replaced James S. Sherman)

William Howard Taft
Republican

Woodrow Wilson
Democratic

The 1912 United States presidential election in Pennsylvania took place on November 5, 1912 throughout the continuous 48 states. This was the first time that Arizona and New Mexico took part in a presidential election having been admitted to the Union earlier in the year. Voters chose 38 representatives, or electors to the Electoral College, who voted for President and Vice President.

This election was a four-way contest. Pennsylvania voted for the Progressive nominee former President Theodore "Teddy" Roosevelt over the Democratic nominee New Jersey Governor Woodrow Wilson, Republican nominee President William Howard Taft, and Socialist Party of America nominee union leader Eugene V. Debs. Roosevelt won Pennsylvania by a margin of 4.04%.