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United States presidential election in South Dakota, 1988

United States presidential election in South Dakota, 1988
South Dakota
1984 ←
November 8, 1988 → 1992

  George H. W. Bush, Vice President of the United States, official portrait.jpg Dukakis1988rally cropped.jpg
Nominee George H. W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 3 0
Popular vote 165,415 145,560
Percentage 52.85% 46.51%

SD1988.jpg

County Results
  Dukakis—70-80%
  Dukakis—60-70%
  Dukakis—50-60%
  Bush—50-60%
  Bush—60-70%
  Bush—70-80%

President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican


SD1988.jpg

Ronald Reagan
Republican

George H. W. Bush
Republican

The 1988 United States presidential election in South Dakota took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. South Dakota voters chose 3 electors to the Electoral College, which selected the President and Vice President.

South Dakota was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.


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