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United States presidential election in Tennessee, 1988

United States presidential election in Tennessee, 1988
Tennessee
← 1984 November 8, 1988 1992 →
  George H. W. Bush, Vice President of the United States, official portrait.jpg Dukakis1988rally cropped.jpg
Nominee George H. W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 11 0
Popular vote 947,233 679,794
Percentage 57.9% 41.6%

TN1988.jpg
County Results
  Dukakis—70-80%
  Dukakis—60-70%
  Dukakis—50-60%
  Bush—50-60%
  Bush—60-70%
  Bush—70-80%

President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican


Ronald Reagan
Republican

George H. W. Bush
Republican

The 1988 United States presidential election in Tennessee took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Tennessee voters chose 11 electors to the Electoral College, which selected the President and Vice President.

Tennessee was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.

Tennessee weighed in for this election as 4% more Republican than the national average.

The presidential election of 1988 was a very partisan election for Tennessee, with more than 99% of the electorate voting for either the Democratic or Republican parties, though 10 candidates did appear on the ballot. Most counties in Tennessee turned out for Bush, including the highly populated Shelby County and Davidson County, by narrow margins. Also, it is interesting to note that Tennessee was the only state that Bush actually improved on Ronald Reagan's 1984 performance, if only by 0.07%.


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