United States presidential election in Wyoming, 1988
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County Results
Bush—<50%
Bush—50-60%
Bush—60-70%
Bush—70-80%
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The 1988 United States presidential election in Wyoming took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Wyoming voters chose 3 electors to the Electoral College, which selected the President and Vice President.
Wyoming was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.
Wyoming weighed in for this election as 7% more Republican than the national average.
The presidential election of 1988 was a very partisan election for Wyoming, with nearly 98% of the electorate voting for either the Democratic or Republican parties, and only 4 candidates on the ballot.
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