Woodall, Oklahoma
| Woodall, Oklahoma | |
|---|---|
| Census-designated place | |
 Location within Cherokee County and the state of Oklahoma |
|
| Coordinates: 35°49′10″N 95°5′8″W / 35.81944°N 95.08556°WCoordinates: 35°49′10″N 95°5′8″W / 35.81944°N 95.08556°W | |
| Country | United States |
| State | Oklahoma |
| County | Cherokee |
| Area | |
| • Total | 11.0 sq mi (28.6 km2) |
| • Land | 11.0 sq mi (28.6 km2) |
| • Water | 0.0 sq mi (0.0 km2) |
| Elevation | 791 ft (241 m) |
| Population (2010) | |
| • Total | 823 |
| • Density | 74/sq mi (28.7/km2) |
| Time zone | Central (CST) (UTC-6) |
| • Summer (DST) | CDT (UTC-5) |
| FIPS code | 40-81912 |
| GNIS feature ID | 1853487 |
Woodall is an unincorporated community and census-designated place (CDP) in Cherokee County, Oklahoma, United States. The population was 823 at the 2010 census.
Woodall is located in western Cherokee County at 35°49′10″N 95°5′8″W / 35.81944°N 95.08556°W (35.819400, -95.085496).U.S. Route 62 forms the southern boundary of the CDP, separating it from Zeb. US-62 leads northeast 9 miles (14 km) to Tahlequah, the Cherokee County seat, and southwest 22 miles (35 km) to Muskogee.
According to the United States Census Bureau, the Woodall CDP has a total area of 11.0 square miles (28.6 km2), all of it land.
As of the census of 2000, there were 741 people, 279 households, and 220 families residing in the CDP. The population density was 66.4 people per square mile (25.6/km²). There were 306 housing units at an average density of 27.4/sq mi (10.6/km²). The racial makeup of the CDP was 56.01% White, 33.06% Native American, 0.81% from other races, and 10.12% from two or more races. Hispanic or Latino of any race were 2.16% of the population.
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